Change file name in Process feed

Replies to This Discussion

Permalink Reply by Martin Wasznicky on October 29, 2013 at 2:54pm

Hi Fred,

if you can, shoot me a sample of what you are doing.  in any case though, make sure you have "Include Metadata" enabled/checked on the adapter endpoints that you are using.

To set the outbound file name for the file adapter endpoint, you can just set either the "file_out.Filename" or "file_in.Filename" property in a Code Process Step.  Either will work and get picked up.  We first check for the "out" property...if that doesn't exist...we check for the "in" property.  We added the "Filename" property a few months back.  you can just set it with the full name and extension like so:

context.data.setproperty("file_out","Filename","mycrazyfile.txt");

This way you don't have to play with multiple properties like "Type" and "Name"

kind regards,

Marty

• ▶ Reply

Permalink Reply by Carlos Tijerina on October 30, 2013 at 8:54am

Worked for .Eat file.. thanks Marty.

• ▶ Reply

Permalink Reply by Carlos Tijerina on October 30, 2013 at 8:41am

Here is the Sample if anyone can help.   Some the file comes in a 60004101010.mix and try to rename. The rename is totally ignored, but the file extension works.

 

string newfilename, infilename;

infilename = context.Data.GetProperty("file_in", "Name");

newfilename = infilename.Substring(5,8) + "_" + infilename.Substring(0,5);

context.Data.SetProperty("file_out", "Name", newfilename);

context.Data.SetProperty("file_out", "Type", "eat");

• ▶ Reply